Question Collected from Telegram Group.
Solution:
P(n):21+22+23+...+2n=2(2n−1)
Step 1: Prove that the statement is true for n=1
P(1):21=2(21−1)
P(1):2=2
Hence, the statement is true for n=1
Step 2: Assume that the statement is true for n=k
Let us assume that the below statement is true:
P(k):2+22+...+2k=
Step 3: Prove that the statement is true for n=k+1
We need to prove that:
2+22...+2k+1=2(2k+1−1)
LHS=2+22+...+2k+2k+1
=2(2k−1)+2k+1
=2(2k−1+2k)
=2(2.2k−1)
=2(2k+1−1)
=RHS
Therefore, P(n) is true for all values of n by
principle of mathematical induction.