Everybody in a room shakes hands with everybody else. The total number of handshakes is 66. The total number of persons in the room are

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Solution:

Let the total number of persons in a room be n since two persons make 1 handshake

The number of handshakes = nC2

So nC2 = 66

⇒$\frac{{n!}}{{2!(n - 2)!}} = 66$

⇒$\frac{{n(n - 1)(n - 2)!}}{{2 \times 1 \times (n - 2)!}} = 66$

⇒$\frac{{n(n - 1)}}{2} = 66$

n2 – n = 132

n2 – n – 132 = 0

n2 – 12n + 11n – 132 = 0

n(n – 12) + 11(n – 12) = 0

(n – 12)(n + 11) = 0

n – 12 = 0, n + 11 = 0

n = 12, n = – 11

n = 12   .... ( n ≠ – 11) 

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