Solution:
Let v₁ and v₂ be the velocities of air above and below surface of
wings.
And P₁ and P₂ be the pressure of the wings.
According to Bernoulli's theorem,
P₁+(1/2) ρ(v₁) ² = P₂+(1/2) ρ(v₂) ²
P₁ - P₂ = (1/2) ρ(v₂²-v₁²)
Here, v₁ = 140 m/s and v₂ = 155 m/s
ρ is the density of air = 1 kg/m³
Area of wings A = 2 × 55 = 110m²
So, P₁ - P₂ = (1/2) ×1×(155²-140²)
= (1/2) × (24025-19600)
= (1/2) × (4425)
= 2212.5
Upward force on the plane = (P₁ - P₂) ×A
= 2212.5×110
= 243375
As the plane is in the level flight, therefore upward force
balances the weight of the plane.
mg = (P₁ - P₂) ×A where m is the mass of Aero plane
m = [(P₁ - P₂) ×A]/g
Here g = 10 (approximately)
m = 243375/10
m = 24337.5 kgs
Hence, Mass of the Aero plane m =
24337.5 kgs